Acid Ionization Constants And Buffer Solutions example essay topic
In part 1, we found the half equivalence point by titrating HA with NaOH, plotting the graph with excel, and then visually finding the halfway mark. The pH at this point was 4.26, which tells us that Ka = 5.50 x 10-5 by knowing pH = pKa and Ka = 10-pKa at the half equivalency point. This means that HA has very little dissociation in an aqueous solution, which is expected because it is a weak acid. In part 2, we were yet again attempting to find the disassociation constant of acetic acid in different solutions by knowing volume, concentration and pH. We found three very different constants, an error which will be covered later. Actually completing these steps was very elementary and does not need to be discussed.
Part 3 was the second half of this lab. We created a buffer solution using 30 mL each of 1.0 M NaA and HA, and the pH was recorded. We then divvied this into two beakers. 2 mL 1.0 M HCl was added to one and 2 mL 1.0 M NaOH was added to the other. The pH level was recorded for each of these solutions.
The original buffer solution had a pH of 4.49. Solution 1 with HCl was 4.30, and Solution 2 with NaOH was 4.55. Previous to this we created an unbuffered solution with DI water and added the same amounts of acid and base to the solution. For HCl, there was a negative 5.62 pH change and positive 4.6 for NaOH.
In the buffered solution, the changes were: HCl - (-0.19); NaOH - (+0.06). This demonstrates the degree to which a buffer solution can resist change. All Ka values determined are far off from the actual 1.76 x 10-5. I believe a very large factor in this is the measuring device itself.
From the beginning there were numerous problems with the pH meters, both with working at all and reading incorrect values. To prove the extent to which the meters were not accurate, in part 2 we conveniently were required to determine the %error. In one solution there was a 61.4% error and in another it was 32.0%. This can very easily throw off all the calculations for the Ka constant. In part 1, either my partner or I made an error in adding 1.0 M HA instead of 0.1 M HA, this caused us to be unable to titrate to the equivalence point with even 50 mL 0.1 M NaOH.