Mass To The Nearest 0 1 example essay topic

Lab Report Title: The Concept and Measurement of Density Purpose: To gain an understanding of the physical property of density. To gain skill in measurement of mass and volume, in addition to the construction of graphs and the physical interpretation of slope. Procedure: Part 1 Regular solids 1. Use the metric ruler to determine the length, width, and height of aluminum and iron cubes to the nearest 0.5 cm. 2. Use the balance to measure the mass of each item listed above to the nearest 0.1 g.

Part 2 Water Displacement 1. Obtain a 50.0 mL graduate cylinder and determine its mass to the nearest 0.1 g. Record in the appropriate space on your data sheet. 2. Fill the graduate cylinder to the 30.0 mL mark with tap water. Remember to read the bottom of the meniscus.

This is the initial volume, V initial. Place the aluminum cylinder and note the final volume, V final. Record the mass of the aluminum cylinder, water, and graduate in the data table. 3.

Repeat step 2, filling the 50.0 mL graduate cylinder to the 30.0 mL mark with tap water, tilt and slowly slide the irregular solid to the bottom. Record the initial and final volumes in the data table. Record the mass of the solid, water, and graduate in the table. 4. Record the mass of the graduate in the row labeled graduate+water+0 pebbles. Repeat this step with 10, 20, and 30 pebbles.

Part 3: Liquids 1. Obtain a container of solution A, and pour it into the graduate cylinder to the 20.0 mL mark. Use a dropper pipe t to obtain an exact reading. 2. Place upon the balance and record the mass to the nearest 0.1 g. 3.

Increase the amount of A to 30.0 mL and find the mass again. 4. Increase the amount of A to 40.0 mL and find the mass again. 5. Increase the amount of A to 50.0 mL and find the mass again. Return A to its original container.

6. Repeat steps 1-5 with solution B. 7. Repeat steps 1-5 with solution C. Analysis and Calculations: 1. Aluminum Cube a. mass = 88.7 volume = 27 density = 2394.92. Iron cube a. mass = 248.5 volume = 21.952 density = 5455.0723. Aluminum Cylinder a. mass = 91.8 volume = 6 density = 550.84.

Pebbles. 0 mass = 74.6 volume = 0 density = 0 b. 10 mass = 92.8 volume = 8 density = 742.4 c. 20 mass = 106 volume = 13 density = 1378d. 30 mass = 121.8 volume = 16 density = 1948.8 Conclusion 1.2.

There is more than zero volume and zero mass because you need some volume to be able to measure the mass. 3.4. Other possible errors in this experiment could me all of the pebbles are different sizes so then they will have different masses. Also some of the objects we used could have been damage in a way so that all of the objects are not all the exact same. And also some of the instruments we used could have been damaged or not up to date..